Chlorine, consisting of two isotopes of mass numbers 35 and 37, has an atomic mass of 35.5.
The relative abundance of the isotope of mass number 37 is?- A. 20
- B. 25
- C. 50
- D. 75
- Let the relative abundance of chlorine with mass of 37 be x%,
- :. the relative abundance of isotopes mass 35=(100-x)%.
- Total mass of isotopes of 37= 37 x,
- while that of 35=(100-x)
- :. Total mass of the 100 atoms=37 x + 35(100-x)=35.5
- 37 x +3500-35x=35.5
- :.Mean mass of chlorine atom=(2x+3500)/100=35.5
- 2 x+3500=3550; x=50/2=25
METHOD TWO
Let A be fraction of Cl-35
And B be fraction of Cl-37
A + B = 1
So B = 1 - A ....eqn1
35 × A + 37 × B = 35.5
35A + 37(1 - A) = 35.5 sub B in eqn1
35A + 37 - 37A = 35.5
-2A = -1.5
A = 0.75
B = 1 - 0.75
B = 0.25
Percentage of Cl-35 = 0.75 ×100 = 75%
Percentage of Cl-37 = 0.25 × 100 = 25%
And B be fraction of Cl-37
A + B = 1
So B = 1 - A ....eqn1
35 × A + 37 × B = 35.5
35A + 37(1 - A) = 35.5 sub B in eqn1
35A + 37 - 37A = 35.5
-2A = -1.5
A = 0.75
B = 1 - 0.75
B = 0.25
Percentage of Cl-35 = 0.75 ×100 = 75%
Percentage of Cl-37 = 0.25 × 100 = 25%
Jamb 1990 Question 12
0 Comments