Equal volumes of CO,SO2, NO2 and H2S were released into a room at the same point and time. Which of the following gives the order of diffusion of the gases to the opposite corner of the room?
(S = 32, C = 12, O = 16, N = 14, H = 1)
- A. CO, SO2,NO2,H2S
- B. SO2,NO2,H2S,CO
- C. CO,H2S,SO2,NO2
- D. CO,H2S,NO2,SO2
Correct Answer: Option D
Explanation
- At a constant temperature and pressure, the rate of diffusion of a gas is inversely proportional to the rate of its relative molecular mass.
- The higher the RMM of a gas the Lower the rate of diffusion and vice versa
- Hence; CO,H2S,NO2,SO2 will be the order of diffusion.
Jamb 1990 question 7
0 Comments