In the reaction: SnO2+2C 一> Sn+2CO, the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is

In the reaction: SnO2+2C 一> Sn+2CO, the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is 

A. 0.40Kg

B. 0.20Kg

C. 0.06Kg 

D. 0.04Kg

[Sn=119, O=16, C=12]

The correct answer is C

First, write the balanced equation:

SnO2 + 2C 一>Sn + 2CO

Step 1: Calculate molar mass of SnO₂

SnO2 = 119 + (2 * 16) = 151  g/mol

Step 2: Find number of moles of SnO₂

Given mass = 0.302 kg = 302 g

Moles of SnO2 = 302/151 = 2  moles

Step 3: Calculate moles of carbon required

From the equation:

• 1 mole of SnO₂ requires 2 moles of C

• 2 moles of SnO₂ require 4 moles of C

Mass of C = 4 * 12 = 48 g

Step 4: Account for coke being 80% carbon

Mass of coke = {48}/{0.80} = 60 g = 0.06  kg

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✅ Correct Answer:

C. 0.06 kg

QUESTION 3