An element A has atomic number 14 and three isotopes 28^A, 29^A, and 30^A with relative abundances of 92.2%, 4.7% and 3.1% respectively, what is the relative atomic mass of the element?
A. 28.109
B. 29.831
C. 28.958
D. 29.815
To find the relative atomic mass, use the weighted average of the isotopes.
Relative atomic mass = (28 * 92.2) + (29 * 4.7) + (30 * 3.1)/100
Calculate:
(28 * 92.2 = 2581.6)
(29 * 4.7 = 136.3)
(30 * 3.1 = 93.0)
Sum:
2581.6 + 136.3 + 93.0 = 2810.9
Divide by 100:
2810.9/100 = 28.109
✅ Correct answer: A. 28.109
PQN: 37
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