Calculate the amount in moles of a gas which occupies 10.5dm^3 at 6 atm. and 30^0C (R=0.82atm dm^-3 K^-1 Mol^-1)

Calculate the amount in moles of a gas which occupies 10.5dm^3 at 6 atm. and 30^0C (R=0.82atm dm^-3 K^-1 Mol^-1)

A. 2.536

B. 1.623

C. 4.736

D. 0.394

Use the ideal gas equation:

PV = nRT
Given:

• (P = 6  atm)

• (V = 10.5 dm^3)

• (T = 30^0C = 303  K)

• (R = 0.082 atm dm^3 K^-1mol^-1) (this is the correct gas constant normally used in exams)

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Step 1: Substitute into the formula

n = PV/RT

n = {6 * 10.5}/{0.082 * 303}

Step 2: Calculate

n = 63/24.846

n = 2.536 mol

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✅ Correct answer: A. 2.536

PQN: 39