What is the volume of a gas at 20^0C if its original volume at 60^0C is 300cm^3? If the pressure is constant
A. 100 cm^3
B. 264 cm^3
C. 900 cm^3
D. 252 cm^3
Calculation:
We are asked to find the new volume of a gas when temperature changes at constant pressure. This is a Charles’s Law problem:
V1/T1 = V2/T2
Where:
V1 = 300 cm³
T1 = 60^0C = 60 + 273 = 333K
T2 = 20^0C = 20 + 273 = 293K
V2 = ?
Step 1: Apply Charles’s Law
V2 = V1*T2/T1
V2 = 300 * 293/333
Step 2: Calculate
293/333approx 0.879
V2 = 300 * 0.879 approx 263.7 approx 264 cm³
✅ Answer: B. 264 cm³
PQN: 7
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