What is the volume of a gas at 20^0C If its original volume at 60^)C is 300 cm^3? If the pressure is constant
A. 100 cm^3
B. 53 cm^3
C. 900 cm^3
D. 264 cm^3
Since the pressure is constant, we apply Charles’ Law:
V1/T1} = V2/T2
Step 1: Convert temperatures to Kelvin
(T1 = 60^0 C = 60 + 273 = 333 , K)
(T2 = 20^0 C = 20 + 273 = 293 , K)
Step 2: Substitute values
300/333 = V2/293
Step 3: Solve for (V2)
V2 = 300*(293/333)
V2=263.96 approx 264 cm^3
✅ Correct answer: D. 264 cm³
PQN: 7
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