Which of the following gives a blue precipitate when NaOH solution is added to it's solution?
A. Cu²+
B. Fe²+
C. Fe³+
D. Pb²+
The correct answer is A. Cu²⁺ ✅
Explanation:
When sodium hydroxide (NaOH) solution is added to a solution containing Cu²⁺ ions, a blue precipitate of copper(II) hydroxide, Cu(OH)₂, is formed.
Cu²⁺ + 2OH⁻ → Cu(OH)₂ (blue precipitate)
Fe²⁺ gives a green precipitate (Fe(OH)₂)
Fe³⁺ gives a brown precipitate (Fe(OH)₃)
Pb²⁺ gives a white precipitate (Pb(OH)₂)
👉 Final Answer: A. Cu²⁺
PQN: 37
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