What mass of copper will be produced from 0.5 Faraday of electricity [Cu=63.5].
A. 63.5g
B. 31.75g
C. 15.88g
D. 7.95g
Apply Faraday’s first law of electrolysis.
Step 1: Write the electrode reaction
Cu^2+ + 2e^- 一> Cu
1 mole of Cu²⁺ requires 2 Faradays to be discharged.
Therefore, 1 Faraday deposits half a mole of Cu.
Step 2: Determine mass deposited by 1 Faraday
Mass by 1 F = Atomic mass/valency = 63.5/2 = 31.75 g
Step 3: Find mass deposited by 0.5 Faraday
Mass = 0.5 * 31.75 = 15.875 approx 15.88 g
✅ Correct answer: C. 15.88 g
Exam tip (WAEC/NECO):
Mass deposited = F * Atomic mass/valency
PQN: 34
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